|  | // Copyright 2005, Google Inc. | 
|  | // All rights reserved. | 
|  | // | 
|  | // Redistribution and use in source and binary forms, with or without | 
|  | // modification, are permitted provided that the following conditions are | 
|  | // met: | 
|  | // | 
|  | //     * Redistributions of source code must retain the above copyright | 
|  | // notice, this list of conditions and the following disclaimer. | 
|  | //     * Redistributions in binary form must reproduce the above | 
|  | // copyright notice, this list of conditions and the following disclaimer | 
|  | // in the documentation and/or other materials provided with the | 
|  | // distribution. | 
|  | //     * Neither the name of Google Inc. nor the names of its | 
|  | // contributors may be used to endorse or promote products derived from | 
|  | // this software without specific prior written permission. | 
|  | // | 
|  | // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS | 
|  | // "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT | 
|  | // LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR | 
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|  | // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. | 
|  |  | 
|  | // A sample program demonstrating using Google C++ testing framework. | 
|  |  | 
|  | #include "sample1.h" | 
|  |  | 
|  | // Returns n! (the factorial of n).  For negative n, n! is defined to be 1. | 
|  | int Factorial(int n) { | 
|  | int result = 1; | 
|  | for (int i = 1; i <= n; i++) { | 
|  | result *= i; | 
|  | } | 
|  |  | 
|  | return result; | 
|  | } | 
|  |  | 
|  | // Returns true iff n is a prime number. | 
|  | bool IsPrime(int n) { | 
|  | // Trivial case 1: small numbers | 
|  | if (n <= 1) return false; | 
|  |  | 
|  | // Trivial case 2: even numbers | 
|  | if (n % 2 == 0) return n == 2; | 
|  |  | 
|  | // Now, we have that n is odd and n >= 3. | 
|  |  | 
|  | // Try to divide n by every odd number i, starting from 3 | 
|  | for (int i = 3; ; i += 2) { | 
|  | // We only have to try i up to the square root of n | 
|  | if (i > n/i) break; | 
|  |  | 
|  | // Now, we have i <= n/i < n. | 
|  | // If n is divisible by i, n is not prime. | 
|  | if (n % i == 0) return false; | 
|  | } | 
|  |  | 
|  | // n has no integer factor in the range (1, n), and thus is prime. | 
|  | return true; | 
|  | } |