| /* Written by Lenka Fibikova <fibikova@exp-math.uni-essen.de> | |
| * and Bodo Moeller for the OpenSSL project. */ | |
| /* ==================================================================== | |
| * Copyright (c) 1998-2000 The OpenSSL Project. All rights reserved. | |
| * | |
| * Redistribution and use in source and binary forms, with or without | |
| * modification, are permitted provided that the following conditions | |
| * are met: | |
| * | |
| * 1. Redistributions of source code must retain the above copyright | |
| * notice, this list of conditions and the following disclaimer. | |
| * | |
| * 2. Redistributions in binary form must reproduce the above copyright | |
| * notice, this list of conditions and the following disclaimer in | |
| * the documentation and/or other materials provided with the | |
| * distribution. | |
| * | |
| * 3. All advertising materials mentioning features or use of this | |
| * software must display the following acknowledgment: | |
| * "This product includes software developed by the OpenSSL Project | |
| * for use in the OpenSSL Toolkit. (http://www.openssl.org/)" | |
| * | |
| * 4. The names "OpenSSL Toolkit" and "OpenSSL Project" must not be used to | |
| * endorse or promote products derived from this software without | |
| * prior written permission. For written permission, please contact | |
| * openssl-core@openssl.org. | |
| * | |
| * 5. Products derived from this software may not be called "OpenSSL" | |
| * nor may "OpenSSL" appear in their names without prior written | |
| * permission of the OpenSSL Project. | |
| * | |
| * 6. Redistributions of any form whatsoever must retain the following | |
| * acknowledgment: | |
| * "This product includes software developed by the OpenSSL Project | |
| * for use in the OpenSSL Toolkit (http://www.openssl.org/)" | |
| * | |
| * THIS SOFTWARE IS PROVIDED BY THE OpenSSL PROJECT ``AS IS'' AND ANY | |
| * EXPRESSED OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE | |
| * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR | |
| * PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE OpenSSL PROJECT OR | |
| * ITS CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, | |
| * SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT | |
| * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; | |
| * LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) | |
| * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, | |
| * STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) | |
| * ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED | |
| * OF THE POSSIBILITY OF SUCH DAMAGE. | |
| * ==================================================================== | |
| * | |
| * This product includes cryptographic software written by Eric Young | |
| * (eay@cryptsoft.com). This product includes software written by Tim | |
| * Hudson (tjh@cryptsoft.com). */ | |
| #include <openssl/bn.h> | |
| #include <openssl/err.h> | |
| #include "internal.h" | |
| BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx) { | |
| // Compute a square root of |a| mod |p| using the Tonelli/Shanks algorithm | |
| // (cf. Henri Cohen, "A Course in Algebraic Computational Number Theory", | |
| // algorithm 1.5.1). |p| is assumed to be a prime. | |
| BIGNUM *ret = in; | |
| int err = 1; | |
| int r; | |
| BIGNUM *A, *b, *q, *t, *x, *y; | |
| int e, i, j; | |
| if (!BN_is_odd(p) || BN_abs_is_word(p, 1)) { | |
| if (BN_abs_is_word(p, 2)) { | |
| if (ret == NULL) { | |
| ret = BN_new(); | |
| } | |
| if (ret == NULL) { | |
| goto end; | |
| } | |
| if (!BN_set_word(ret, BN_is_bit_set(a, 0))) { | |
| if (ret != in) { | |
| BN_free(ret); | |
| } | |
| return NULL; | |
| } | |
| return ret; | |
| } | |
| OPENSSL_PUT_ERROR(BN, BN_R_P_IS_NOT_PRIME); | |
| return (NULL); | |
| } | |
| if (BN_is_zero(a) || BN_is_one(a)) { | |
| if (ret == NULL) { | |
| ret = BN_new(); | |
| } | |
| if (ret == NULL) { | |
| goto end; | |
| } | |
| if (!BN_set_word(ret, BN_is_one(a))) { | |
| if (ret != in) { | |
| BN_free(ret); | |
| } | |
| return NULL; | |
| } | |
| return ret; | |
| } | |
| BN_CTX_start(ctx); | |
| A = BN_CTX_get(ctx); | |
| b = BN_CTX_get(ctx); | |
| q = BN_CTX_get(ctx); | |
| t = BN_CTX_get(ctx); | |
| x = BN_CTX_get(ctx); | |
| y = BN_CTX_get(ctx); | |
| if (y == NULL) { | |
| goto end; | |
| } | |
| if (ret == NULL) { | |
| ret = BN_new(); | |
| } | |
| if (ret == NULL) { | |
| goto end; | |
| } | |
| // A = a mod p | |
| if (!BN_nnmod(A, a, p, ctx)) { | |
| goto end; | |
| } | |
| // now write |p| - 1 as 2^e*q where q is odd | |
| e = 1; | |
| while (!BN_is_bit_set(p, e)) { | |
| e++; | |
| } | |
| // we'll set q later (if needed) | |
| if (e == 1) { | |
| // The easy case: (|p|-1)/2 is odd, so 2 has an inverse | |
| // modulo (|p|-1)/2, and square roots can be computed | |
| // directly by modular exponentiation. | |
| // We have | |
| // 2 * (|p|+1)/4 == 1 (mod (|p|-1)/2), | |
| // so we can use exponent (|p|+1)/4, i.e. (|p|-3)/4 + 1. | |
| if (!BN_rshift(q, p, 2)) { | |
| goto end; | |
| } | |
| q->neg = 0; | |
| if (!BN_add_word(q, 1) || | |
| !BN_mod_exp_mont(ret, A, q, p, ctx, NULL)) { | |
| goto end; | |
| } | |
| err = 0; | |
| goto vrfy; | |
| } | |
| if (e == 2) { | |
| // |p| == 5 (mod 8) | |
| // | |
| // In this case 2 is always a non-square since | |
| // Legendre(2,p) = (-1)^((p^2-1)/8) for any odd prime. | |
| // So if a really is a square, then 2*a is a non-square. | |
| // Thus for | |
| // b := (2*a)^((|p|-5)/8), | |
| // i := (2*a)*b^2 | |
| // we have | |
| // i^2 = (2*a)^((1 + (|p|-5)/4)*2) | |
| // = (2*a)^((p-1)/2) | |
| // = -1; | |
| // so if we set | |
| // x := a*b*(i-1), | |
| // then | |
| // x^2 = a^2 * b^2 * (i^2 - 2*i + 1) | |
| // = a^2 * b^2 * (-2*i) | |
| // = a*(-i)*(2*a*b^2) | |
| // = a*(-i)*i | |
| // = a. | |
| // | |
| // (This is due to A.O.L. Atkin, | |
| // <URL: | |
| //http://listserv.nodak.edu/scripts/wa.exe?A2=ind9211&L=nmbrthry&O=T&P=562>, | |
| // November 1992.) | |
| // t := 2*a | |
| if (!bn_mod_lshift1_consttime(t, A, p, ctx)) { | |
| goto end; | |
| } | |
| // b := (2*a)^((|p|-5)/8) | |
| if (!BN_rshift(q, p, 3)) { | |
| goto end; | |
| } | |
| q->neg = 0; | |
| if (!BN_mod_exp_mont(b, t, q, p, ctx, NULL)) { | |
| goto end; | |
| } | |
| // y := b^2 | |
| if (!BN_mod_sqr(y, b, p, ctx)) { | |
| goto end; | |
| } | |
| // t := (2*a)*b^2 - 1 | |
| if (!BN_mod_mul(t, t, y, p, ctx) || | |
| !BN_sub_word(t, 1)) { | |
| goto end; | |
| } | |
| // x = a*b*t | |
| if (!BN_mod_mul(x, A, b, p, ctx) || | |
| !BN_mod_mul(x, x, t, p, ctx)) { | |
| goto end; | |
| } | |
| if (!BN_copy(ret, x)) { | |
| goto end; | |
| } | |
| err = 0; | |
| goto vrfy; | |
| } | |
| // e > 2, so we really have to use the Tonelli/Shanks algorithm. | |
| // First, find some y that is not a square. | |
| if (!BN_copy(q, p)) { | |
| goto end; // use 'q' as temp | |
| } | |
| q->neg = 0; | |
| i = 2; | |
| do { | |
| // For efficiency, try small numbers first; | |
| // if this fails, try random numbers. | |
| if (i < 22) { | |
| if (!BN_set_word(y, i)) { | |
| goto end; | |
| } | |
| } else { | |
| if (!BN_pseudo_rand(y, BN_num_bits(p), 0, 0)) { | |
| goto end; | |
| } | |
| if (BN_ucmp(y, p) >= 0) { | |
| if (!(p->neg ? BN_add : BN_sub)(y, y, p)) { | |
| goto end; | |
| } | |
| } | |
| // now 0 <= y < |p| | |
| if (BN_is_zero(y)) { | |
| if (!BN_set_word(y, i)) { | |
| goto end; | |
| } | |
| } | |
| } | |
| r = bn_jacobi(y, q, ctx); // here 'q' is |p| | |
| if (r < -1) { | |
| goto end; | |
| } | |
| if (r == 0) { | |
| // m divides p | |
| OPENSSL_PUT_ERROR(BN, BN_R_P_IS_NOT_PRIME); | |
| goto end; | |
| } | |
| } while (r == 1 && ++i < 82); | |
| if (r != -1) { | |
| // Many rounds and still no non-square -- this is more likely | |
| // a bug than just bad luck. | |
| // Even if p is not prime, we should have found some y | |
| // such that r == -1. | |
| OPENSSL_PUT_ERROR(BN, BN_R_TOO_MANY_ITERATIONS); | |
| goto end; | |
| } | |
| // Here's our actual 'q': | |
| if (!BN_rshift(q, q, e)) { | |
| goto end; | |
| } | |
| // Now that we have some non-square, we can find an element | |
| // of order 2^e by computing its q'th power. | |
| if (!BN_mod_exp_mont(y, y, q, p, ctx, NULL)) { | |
| goto end; | |
| } | |
| if (BN_is_one(y)) { | |
| OPENSSL_PUT_ERROR(BN, BN_R_P_IS_NOT_PRIME); | |
| goto end; | |
| } | |
| // Now we know that (if p is indeed prime) there is an integer | |
| // k, 0 <= k < 2^e, such that | |
| // | |
| // a^q * y^k == 1 (mod p). | |
| // | |
| // As a^q is a square and y is not, k must be even. | |
| // q+1 is even, too, so there is an element | |
| // | |
| // X := a^((q+1)/2) * y^(k/2), | |
| // | |
| // and it satisfies | |
| // | |
| // X^2 = a^q * a * y^k | |
| // = a, | |
| // | |
| // so it is the square root that we are looking for. | |
| // t := (q-1)/2 (note that q is odd) | |
| if (!BN_rshift1(t, q)) { | |
| goto end; | |
| } | |
| // x := a^((q-1)/2) | |
| if (BN_is_zero(t)) // special case: p = 2^e + 1 | |
| { | |
| if (!BN_nnmod(t, A, p, ctx)) { | |
| goto end; | |
| } | |
| if (BN_is_zero(t)) { | |
| // special case: a == 0 (mod p) | |
| BN_zero(ret); | |
| err = 0; | |
| goto end; | |
| } else if (!BN_one(x)) { | |
| goto end; | |
| } | |
| } else { | |
| if (!BN_mod_exp_mont(x, A, t, p, ctx, NULL)) { | |
| goto end; | |
| } | |
| if (BN_is_zero(x)) { | |
| // special case: a == 0 (mod p) | |
| BN_zero(ret); | |
| err = 0; | |
| goto end; | |
| } | |
| } | |
| // b := a*x^2 (= a^q) | |
| if (!BN_mod_sqr(b, x, p, ctx) || | |
| !BN_mod_mul(b, b, A, p, ctx)) { | |
| goto end; | |
| } | |
| // x := a*x (= a^((q+1)/2)) | |
| if (!BN_mod_mul(x, x, A, p, ctx)) { | |
| goto end; | |
| } | |
| while (1) { | |
| // Now b is a^q * y^k for some even k (0 <= k < 2^E | |
| // where E refers to the original value of e, which we | |
| // don't keep in a variable), and x is a^((q+1)/2) * y^(k/2). | |
| // | |
| // We have a*b = x^2, | |
| // y^2^(e-1) = -1, | |
| // b^2^(e-1) = 1. | |
| if (BN_is_one(b)) { | |
| if (!BN_copy(ret, x)) { | |
| goto end; | |
| } | |
| err = 0; | |
| goto vrfy; | |
| } | |
| // find smallest i such that b^(2^i) = 1 | |
| i = 1; | |
| if (!BN_mod_sqr(t, b, p, ctx)) { | |
| goto end; | |
| } | |
| while (!BN_is_one(t)) { | |
| i++; | |
| if (i == e) { | |
| OPENSSL_PUT_ERROR(BN, BN_R_NOT_A_SQUARE); | |
| goto end; | |
| } | |
| if (!BN_mod_mul(t, t, t, p, ctx)) { | |
| goto end; | |
| } | |
| } | |
| // t := y^2^(e - i - 1) | |
| if (!BN_copy(t, y)) { | |
| goto end; | |
| } | |
| for (j = e - i - 1; j > 0; j--) { | |
| if (!BN_mod_sqr(t, t, p, ctx)) { | |
| goto end; | |
| } | |
| } | |
| if (!BN_mod_mul(y, t, t, p, ctx) || | |
| !BN_mod_mul(x, x, t, p, ctx) || | |
| !BN_mod_mul(b, b, y, p, ctx)) { | |
| goto end; | |
| } | |
| e = i; | |
| } | |
| vrfy: | |
| if (!err) { | |
| // verify the result -- the input might have been not a square | |
| // (test added in 0.9.8) | |
| if (!BN_mod_sqr(x, ret, p, ctx)) { | |
| err = 1; | |
| } | |
| if (!err && 0 != BN_cmp(x, A)) { | |
| OPENSSL_PUT_ERROR(BN, BN_R_NOT_A_SQUARE); | |
| err = 1; | |
| } | |
| } | |
| end: | |
| if (err) { | |
| if (ret != in) { | |
| BN_clear_free(ret); | |
| } | |
| ret = NULL; | |
| } | |
| BN_CTX_end(ctx); | |
| return ret; | |
| } | |
| int BN_sqrt(BIGNUM *out_sqrt, const BIGNUM *in, BN_CTX *ctx) { | |
| BIGNUM *estimate, *tmp, *delta, *last_delta, *tmp2; | |
| int ok = 0, last_delta_valid = 0; | |
| if (in->neg) { | |
| OPENSSL_PUT_ERROR(BN, BN_R_NEGATIVE_NUMBER); | |
| return 0; | |
| } | |
| if (BN_is_zero(in)) { | |
| BN_zero(out_sqrt); | |
| return 1; | |
| } | |
| BN_CTX_start(ctx); | |
| if (out_sqrt == in) { | |
| estimate = BN_CTX_get(ctx); | |
| } else { | |
| estimate = out_sqrt; | |
| } | |
| tmp = BN_CTX_get(ctx); | |
| last_delta = BN_CTX_get(ctx); | |
| delta = BN_CTX_get(ctx); | |
| if (estimate == NULL || tmp == NULL || last_delta == NULL || delta == NULL) { | |
| OPENSSL_PUT_ERROR(BN, ERR_R_MALLOC_FAILURE); | |
| goto err; | |
| } | |
| // We estimate that the square root of an n-bit number is 2^{n/2}. | |
| if (!BN_lshift(estimate, BN_value_one(), BN_num_bits(in)/2)) { | |
| goto err; | |
| } | |
| // This is Newton's method for finding a root of the equation |estimate|^2 - | |
| // |in| = 0. | |
| for (;;) { | |
| // |estimate| = 1/2 * (|estimate| + |in|/|estimate|) | |
| if (!BN_div(tmp, NULL, in, estimate, ctx) || | |
| !BN_add(tmp, tmp, estimate) || | |
| !BN_rshift1(estimate, tmp) || | |
| // |tmp| = |estimate|^2 | |
| !BN_sqr(tmp, estimate, ctx) || | |
| // |delta| = |in| - |tmp| | |
| !BN_sub(delta, in, tmp)) { | |
| OPENSSL_PUT_ERROR(BN, ERR_R_BN_LIB); | |
| goto err; | |
| } | |
| delta->neg = 0; | |
| // The difference between |in| and |estimate| squared is required to always | |
| // decrease. This ensures that the loop always terminates, but I don't have | |
| // a proof that it always finds the square root for a given square. | |
| if (last_delta_valid && BN_cmp(delta, last_delta) >= 0) { | |
| break; | |
| } | |
| last_delta_valid = 1; | |
| tmp2 = last_delta; | |
| last_delta = delta; | |
| delta = tmp2; | |
| } | |
| if (BN_cmp(tmp, in) != 0) { | |
| OPENSSL_PUT_ERROR(BN, BN_R_NOT_A_SQUARE); | |
| goto err; | |
| } | |
| ok = 1; | |
| err: | |
| if (ok && out_sqrt == in && !BN_copy(out_sqrt, estimate)) { | |
| ok = 0; | |
| } | |
| BN_CTX_end(ctx); | |
| return ok; | |
| } |